'use strict';

Object.defineProperty(exports, "__esModule", {
  value: true
});
exports.createCsSpsolve = void 0;

var _csReach = require("./csReach");

var _factory = require("../../../utils/factory");

var name = 'csSpsolve';
var dependencies = ['divideScalar', 'multiply', 'subtract'];
var createCsSpsolve =
/* #__PURE__ */
(0, _factory.factory)(name, dependencies, function (_ref) {
  var divideScalar = _ref.divideScalar,
      multiply = _ref.multiply,
      subtract = _ref.subtract;

  /**
   * The function csSpsolve() computes the solution to G * x = bk, where bk is the
   * kth column of B. When lo is true, the function assumes G = L is lower triangular with the
   * diagonal entry as the first entry in each column. When lo is true, the function assumes G = U
   * is upper triangular with the diagonal entry as the last entry in each column.
   *
   * @param {Matrix}  g               The G matrix
   * @param {Matrix}  b               The B matrix
   * @param {Number}  k               The kth column in B
   * @param {Array}   xi              The nonzero pattern xi[top] .. xi[n - 1], an array of size = 2 * n
   *                                  The first n entries is the nonzero pattern, the last n entries is the stack
   * @param {Array}   x               The soluton to the linear system G * x = b
   * @param {Array}   pinv            The inverse row permutation vector, must be null for L * x = b
   * @param {boolean} lo              The lower (true) upper triangular (false) flag
   *
   * @return {Number}                 The index for the nonzero pattern
   *
   * Reference: http://faculty.cse.tamu.edu/davis/publications.html
   */
  return function csSpsolve(g, b, k, xi, x, pinv, lo) {
    // g arrays
    var gvalues = g._values;
    var gindex = g._index;
    var gptr = g._ptr;
    var gsize = g._size; // columns

    var n = gsize[1]; // b arrays

    var bvalues = b._values;
    var bindex = b._index;
    var bptr = b._ptr; // vars

    var p, p0, p1, q; // xi[top..n-1] = csReach(B(:,k))

    var top = (0, _csReach.csReach)(g, b, k, xi, pinv); // clear x

    for (p = top; p < n; p++) {
      x[xi[p]] = 0;
    } // scatter b


    for (p0 = bptr[k], p1 = bptr[k + 1], p = p0; p < p1; p++) {
      x[bindex[p]] = bvalues[p];
    } // loop columns


    for (var px = top; px < n; px++) {
      // x array index for px
      var j = xi[px]; // apply permutation vector (U x = b), j maps to column J of G

      var J = pinv ? pinv[j] : j; // check column J is empty

      if (J < 0) {
        continue;
      } // column value indeces in G, p0 <= p < p1


      p0 = gptr[J];
      p1 = gptr[J + 1]; // x(j) /= G(j,j)

      x[j] = divideScalar(x[j], gvalues[lo ? p0 : p1 - 1]); // first entry L(j,j)

      p = lo ? p0 + 1 : p0;
      q = lo ? p1 : p1 - 1; // loop

      for (; p < q; p++) {
        // row
        var i = gindex[p]; // x(i) -= G(i,j) * x(j)

        x[i] = subtract(x[i], multiply(gvalues[p], x[j]));
      }
    } // return top of stack


    return top;
  };
});
exports.createCsSpsolve = createCsSpsolve;